[2024/05/13] Irrational powers
- Show that it’s possible
a^b=c
wherea
andb
are irrational, andc
is rational.
Sry for the gap I ran out of ideas.
a^b=c
where a
and b
are irrational, and c
is rational.Sry for the gap I ran out of ideas.
zkfcfbzr, (edited ) solutione^(i*π) = -1 Also, anything like a^(log(c) / log(a)), for positive rational c and irrational a, to generalize bean_jamming’s answer I also assert without proof that in the equation x^x = c, x is irrational for most rational values of c I did start trying out stuff with sqrt(2), thinking back to the tower power problems, but didn’t end up coming up with your solution while doing so ¯_(ツ)_/¯
been_jamming, e^(log 2) = 2 is rational
siriusmart, that is simply genius
(i suppose it didnt come to me when i think of “irrational”)
siriusmart, (edited ) this one got some table slams from my friends
Hint:
spoilerFind an example which satisfies the equation.
Solution:
spoiler…siri.sh/…/2024-05-13_irrational-powers.htmlhttps://lemmy.world/pictrs/image/94a2af80-483f-4874-9864-ca1858e61546.png
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