Trying out the problems to see how my Indian education(Kerala state govt college education) helps me:
In the denominator there is a common a on both sides and can be cancelled. In the right hand side there’s a common c which can be simplified.
And the numerator on the left can be multiplied by 2/2
We can write 4a^2^(b+c)^2n^ as (2a(b+c)^n^)^2^
Then using x^2^ - y^2^ = (x - y) (x + y) we can simplify the numerator.
3 > ln(x)
Edit: ln(x) is bounded on both sides here. Thanking u/ AernaLingus for pointing that out
The complete answer would be 1/2 < ln(x) < 3
Thanking them again.
x = e^(-3 ln(3)/(30 - ln(3)^)
What’s tg?
Is it tangent? Assumed that and got x = cos^-1^(1/3) = 1.23095
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