stevensanderson,
@stevensanderson@mstdn.social avatar
jameslairdsmith,

@stevensanderson You can also use `lubridate::days_in_month()’ which is perhaps more straightforward.

stevensanderson,
@stevensanderson@mstdn.social avatar

@jameslairdsmith @stevensanderson true but i like to also when i know how, show a base R solution

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