I have a list of 3 python objects w/ 4 attributes. If exactly 2 are identical (not all 3, not none) I want to return False.
mylist=[ob1, obj2, obj3]
if len(set([x.attribute1 for x in mylist]))==2:
return False
if len(set([x.attribute2 for x in mylist]))==2:
return False
if len(set([x.attribute3 for x in mylist]))==2:
return False
if len(set([x.attribute4 for x in mylist]))==2:
return False
return True
@futurebird The cool thing is that this property is invariant under S_3 actions on the underlying set of alternatives, even if it is expressed in Z/3Z language. Now I'm trying to think if there's a reasonable 4-dimensional extension, in which four cards with four alternatives per attribute form a set iff they are coplanar in (Z/4Z)^n and no three are collinear.
@futurebird Thinking about it more clearly: the property of being coplanar with no three points collinear is not unique even over Z/3Z: for each set of three non-collinear points in (Z/3Z)^n, n \geq 2, there are three points on the plane they span that are not collinear with any two.
There already is a game based on this property. It's defined as, four cards form a *set if there is a way to divide them into two pairs, such as that each of the two pairs forms a set with the same card.
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